[extropy-chat] Monty Hall Paradox ... Not!
Rob Wilkes
robwilkes at satx.rr.com
Thu May 20 05:36:06 UTC 2004
The Monty Hall Paradox is not a paradox. Think of it from Monty's POV. MH
must have an envelope to swap you for each time that he offers a trade. In
the worst case (for Monty) he would keep offering you an envelope
containing twice as much and you would keep trading. For 5 trades the
progression would be: $10 (start), 20, 40, 80, 160, 320. You started with
$10 and walked away with $320. In the best case for MH he would keep
offering you an envelope containing half as much and you would keep
trading. For 5 trades the progression would be: $10 (start), 5, 2.50,
1.25, 0.625, 0.3125. You started with $10 and walked away with $0.3125.
Your luck could go either way 50:50 on each trade. It is essentially a
random walk along a 1-dimensional integer line where the value at each
integer is $10 x 2^i. (i being the integer, and 0 being the starting
point.) The number of trades determines the liability MH is at risk for:
$10 x 2^n, where n is the number of trades he will offer you. If Monty
will offer you 8 trades, starting with $10, then he must be prepared to
fork over $10 x 2^8 = $2560.00 in the worst case. The probablilty of you
getting that lucky is 1/(2^8) = 1/16. For 8 trades you have an equal chance
of walking away with any of the following: $2560, 1280, 640, 320, 160, 80,
40, 20, $10, 5, 2.50, 1.25, 0.625, 0.3125, 0.15625, 0.078125, $0.039063.
You can only get rich by being lucky and trading a lot. You can only get
very poor by being unlucky and trading a lot. If you don't trade at all
you have $10 to buy some beer for you and your friends after the show, and
that is the only outcome that is guaranteed.
Rob Wilkes
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