[extropy-chat] glat test
Simon Dawson
extropians at perception.co.nz
Sat Oct 30 03:35:30 UTC 2004
At 15:56 30/10/2004, you wrote:
>> Simon Dawson
>
>>
>> you know, the thought occurs to me. Often these kinds of
>> tests are the "aha" kind.
>>
>> ie, there's a trick.
>>
>> in this problem, resistance across a knight's move, perhaps
>> the clue is really "the grid of resistors"
>>
>> a grid implies square pattern, right?
>>
>> which means you'd have to go UP two resistors, and ACROSS
>> one, to get the knight's move.
>>
>> this would mean the sum of 3 resistances.
>>
>> Just a thought.
>>
>> Si
>
>
>Well sure. The way I interpreted the problem is a grid of
>squares. If node A is at (0,0) and node B is at (1,2)
>and there is a one-ohm resistor between each node, what
>is Req between A and B? I have solved the case for two
>adjacent nodes and two nodes diagonally separated, but
>I cannot add the two resistances to get Req A-B. If I
>did, I would be remarkably close to 1 ohm, so I am tempted
>to say that is the answer, but I want to prove it. Its
>turned out to be wildly difficult.
hmm yes. don't remember enough electronics to solve it.
however, I suggest you -don't- look at this
http://www.geocities.com/frooha/grid/node2.html
:)
Si
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