[extropy-chat] glat test

[Simon Dawson]

At 15:56 30/10/2004, you wrote:

>> Simon Dawson
>
>> 
>> you know, the thought occurs to me. Often these kinds of 
>> tests are the "aha" kind.
>> 
>> ie, there's a trick.
>> 
>> in this problem, resistance across a knight's move, perhaps 
>> the clue is really "the grid of resistors"
>> 
>> a grid implies square pattern, right?
>> 
>> which means you'd have to go UP two resistors, and ACROSS 
>> one, to get the knight's move.
>> 
>> this would mean the sum of 3 resistances.
>> 
>> Just a thought.
>> 
>> Si
>
>
>Well sure.  The way I interpreted the problem is a grid of
>squares.  If node A is at (0,0) and node B is at (1,2)
>and there is a one-ohm resistor between each node, what
>is Req between A and B?  I have solved the case for two
>adjacent nodes and two nodes diagonally separated, but
>I cannot add the two resistances to get Req A-B.  If I
>did, I would be remarkably close to 1 ohm, so I am tempted
>to say that is the answer, but I want to prove it.  Its
>turned out to be wildly difficult.

hmm yes. don't remember enough electronics to solve it.

however, I suggest you -don't- look at this

http://www.geocities.com/frooha/grid/node2.html

:)

Si