[ExI] QT and SR

The Avantguardian avantguardian2020 at yahoo.com
Mon Aug 25 09:57:46 UTC 2008


Just wanted to correct some typos.

--- The Avantguardian <avantguardian2020 at yahoo.com> wrote:
> Case 1- No string:
> 
> At the point the ships reach .7071 light speed, the rear ship bounces a radar
> signal off of the stern of the front ship. The radar would read the distance
> between the ships at 100 meters*(1+ sqrt(1-(.7071c)^2)) or about 129.29
> meters.
> In other words, the length of the spaceships themselves contracted from 100
> meters long each to 70.71 meters long each but their centers of mass remained
> the same 100 meters distance apart.

The centers of mass would remain 200 meters apart.

 
> Case 2- a string connects the spaceships:
> To asses what happens when you join the two spaceships stem to stern with a
> 100
> meter string, one must realize that as John Clark said, both the space ships
> and the string have to skrink. So lets say that as in the first example they
> start out at rest and accelerate at 250.53 g. Now in the 24 hours that the
> ships accelerated to .7071 lightspeed, the string would have to shrink by by
> 100 meters*(1- sqrt(1-(.7071c)^2))=29.29 meters due to its own relativistic
> contraction winding up a mere 70.71 meters long just like either of the two

The equation above should read 100 meters*(1- sqrt(1-(.7071)^2))=29.29 meters.




Stuart LaForge

"A portion of mankind take pride in their vices and pursue their purpose; many more waver between doing what is right and complying with what is wrong." - Horace


      



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