[ExI] Physical limits of electromagnetic launchers
Anders Sandberg
anders at aleph.se
Sun Jun 3 14:15:31 UTC 2012
OK, let's say I want to send off my payload using a circular launcher.
Then it needs to hold against a centipetal force of mv^2/r (what is the
relativistic version of this formula, BTW?)
For v on the order of 0.1c and m=0.03 kg, the force will be 2.7e13/r. So
assuming materials can handle a few hundred gigapascals (what we get in
diamond anvils) and that the payload is nice and flat with an area of
0.01 m^2 (it is not actully pressed against the accelerator, but the EM
fields will transfer the force) I get a max acceptable force of 10^9 N,
which corresponds to r > 27 km. Thats actully not bad at all.
I suspect the real problem is coupling the accelerating fields with the
payload without losing too much in Bremsstrahlung. It scales with the
square of the acceleration for both circular paths and linear ones, but
in the linear case there is also a sixth power dependency on gamma,
while the circular one is just to the fourht power.
[ OK, think I found a derivation of the relativistic formula:
http://www.physicsforums.com/showthread.php?t=187041
So the force would be mv^2/R(1-v^2/c^2) - for a 90% c payload the
relativistic correction makes the force about 5 times larger, and in
this case the radius need to be about 11,000 km. Still small. I think
this approach has merit. ]
On 02/06/2012 23:36, Jeff Davis wrote:
> So could you try again, dispensing with the electric charge business
> and just going with maglev or something similar.
But maglev is electric charge, when you start looking at it
relativistically! A pure magnetic field will look like it has electrical
components when you move through it fast enough.
--
Anders Sandberg,
Future of Humanity Institute
Philosophy Faculty of Oxford University
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