[ExI] re end of world
rex
rex at nosyntax.net
Fri Sep 11 05:03:21 UTC 2015
Rafal Smigrodzki <rafal.smigrodzki at gmail.com> [2015-09-10 17:10]:
> On Thu, Sep 10, 2015 at 6:38 PM, Anders Sandberg <[1]anders at aleph.se>
> wrote:
> What is going on is that the intelligence is due to a lot of genes
> adding about 1% or less each, so removing the <150 IQ population mainly
> removes some very bad genes and decreases the somewhat bad genes: there
> is still a lot of genetic diversity. So the new mean goes up, but the
> variance stays about the same.
>
> Are you sure the variance would stay the same? Wouldn't
> removing 99.9570883466% of the population from the reproductive pool lower
> diversity?
> The IQ of their offspring would be of course less than 150, with
> regression to the mean, but there would be still a substantial boost over
> the current average, to about 130
> ([2]http://infoproc.blogspot.com/2010/07/assortative-mating-regression-and-all.html)
> and the residual SD would be about 12.
Good find, Rafał!
I worked on this some years ago and never was able to create a chromosome model
(with crossover, etc) where the variance didn't grow over generations.
A model often used to predict offspring IQ (or other heritable
polygenic trait) is:
oiq = m + h^2*(p-m) (Crow)
where oiq is the mean IQ of the offspring, h^2 is the narrow
heritability, m = population mean IQ, and m = parental mean IQ.
For IQ, IMO, 0.7 is a reasonable value for h^2 (The heritability of IQ increases
with age and childhood estimates underestimate the adult heritability of IQ.)
I think the value of rho (correlation of mate IQ due to assortative
mating) is fairly "soft," and use 0.25.
R makes it easy to simulate the process.
pop = rnorm(9e6, 100, 16) #generate 9 million Gaussian randoms, mean 100, SD 16
N1 = 1000 #size of high-IQ breeder population
hiq = numeric(N1) #IQs of breeders
minIQ = 150 #minimum IQ of breeders
cnt = i = 1 #pointers
while (cnt <= N1){ #do until quota filled
if (pop[i] >= minIQ){ #qualified
hiq[cnt] = pop[i] #add individual to breeder population
cnt = cnt + 1 #bump number of breeders
}
i = i + 1
}
mean(hiq)
[1] 154.4818
sd(hiq)
[1] 4.12788
plot(density(hiq),main='Minimum IQ 150', xlab='IQ')
As the graph shows, the selected group with minimum IQ has a skewed
distribution. Roughly, the offspring of this group would be expected
to have a mean IQ of:
oiq = 100 + 0.7*(154.5-100) = 138
It would be a very different world, and IQ would drift toward whatever value
was currently selected for.
> A good reason to make and sequence thousands of zygotes before proceeding
> to term. For the squeamish you might try to develop a post-meiotic gamete
> cloning procedure, followed by mass sequencing and zygote generation from
> vetted but otherwise unmodified gametes.
The mean IQ could be dramatically raised if IQ could be estimated from a cell from
blastocyts. Couples could pick the highest IQ blastocyst from, say, 5. I've a web page
that illustrates mean population IQ over generations if some fraction of parents
follow such a procedure. If there's interest I'll put it on the WWW again.
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