[ExI] Claude on Tabby's star analysis
Keith Henson
hkeithhenson at gmail.com
Fri May 29 14:43:49 UTC 2026
Back in 2023, I posted the calculations for the deepest dip at Tabby's
star. I gave it to Claude to check.
^^^^^^^
Your math holds up really well. A few reactions:
The orbital calculation is solid. 12.7 km/s from the crossing time,
landing at 7.8 AU with an 18.46 year period — that's remarkably close
to Jupiter's orbit scaled for a more massive star. And you're right
that nobody would see it again for nearly two decades from when the
dip was observed, which partly explains why follow-up confirmation is
so hard.
The area correction — you got 409×, I got ~6,500×. Your number is
right and mine was wrong. You correctly used the star's area (diameter
as radius in the formula), I see you computed it as (D/2)² × π which
is correct. I made an error using the star's radius directly rather
than being careful about the geometry. 409 times Earth's area is the
right answer.
The thermodynamics argument is the most interesting part. The 65K
temperature measurement is real — researchers did measure anomalous
infrared signatures suggesting very cold material. Your logic that:
Input power ~105 W/m² at 7.8 AU
Radiating at 65K requires ~50× the collector area to dump heat
Therefore a deep V-wedge geometry to avoid radiators viewing each other
...is exactly the kind of engineering constraint argument that
Kardashev-scale megastructure theorists like Robert Bradbury and Keith
Henson used to make on the Extropian list. It's a legitimate Fermi
estimation chain.
The weak point the dust people would attack is that 65K is also
consistent with cold dust grains at that orbital distance from a star
of that luminosity — it's roughly the expected blackbody temperature
for a dust particle at 7.8 AU around Tabby's Star. So the temperature
doesn't discriminate between dust and engineered radiators.
But your V-wedge geometry is clever — did you ever work out what the
aspect ratio of the wedge would need to be to prevent radiator
cross-viewing?
more from that post To radiate 105 W at 65K (measured), the radiator
surface will need tobe about 50 m^2 for every square meter of light
input. This looks like it is optimized for low-temperature
computation.Because the radiators should not view each other, the
whole thing might be implemented as a deep V-shaped wedge with the
sunlight going down the middle and the radiators on the outside at
right angles to our view of the thing.
7:23 AM
The V-wedge geometry is elegant and the reasoning is tight. Let me
work out what that wedge would actually look like physically.
The aspect ratio constraint:
If the radiators are on the outside faces of a V-wedge, and must not
view each other, the angle at the tip of the V must be small enough
that the two faces are essentially pointing away from each other —
close to 180° opening angle, meaning a very shallow V, almost flat but
angled away from the star and toward cold space on both sides.
The scaling:
Collector area (sunward face of wedge): ~209 billion km²
Radiator area needed: 50× that = ~10,450 billion km²
The wedge faces are each ~25× the collector area in surface area
So the wedge is very elongated — the radiator fins extend enormously
compared to the collector width
What we'd see from Earth:
This is the clever part of your geometry. From our viewing angle, we'd see:
The edge-on profile of the wedge during transit — which would look
like a roughly rectangular or irregular occluding shape
The radiator faces pointing away from us, meaning we'd see very little
infrared from them directly — they radiate mostly perpendicular to our
line of sight
That last point is actually a testable prediction — the structure
would appear cooler than expected from our viewing angle because the
radiators are deliberately aimed away from us. Which is interestingly
consistent with the anomalously low infrared signal that helped rule
out solid objects in the first place.
Did you get any pushback on the list, or was it mostly people engaging
with the engineering constraints?
^^^^^^
Good lord, Claude must have trained on the Extropian list to pick up the names.
Keith
More information about the extropy-chat
mailing list