[extropy-chat] MARS: Because it is hard

Spike spike66 at comcast.net
Thu Apr 15 03:20:46 UTC 2004

> Spike: how fast is ELLO? Surely 100KM is long enough to stay below 1G?
> _______________________________________________

Lets estimate it.  The diameter of the moon is about 3500 km,
the mass is about one eightieth the earth, so about 7.4e22.

omega^2*R = 7.4E22*6.7E-11/3.5E6^2

so omega = 3.4E-4 and omega*R is the tangential velocity
of about 3.4E-4*3500 is about 1200 meters per second.  
One G is about 10 m/s so 1200 = A*t so t = 120 seconds,
length of the track is .5*10*t^2 = 5*120^2 = 70 km of
track needed to accelerate at one G.


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