[extropy-chat] MARS: Because it is hard
spike66 at comcast.net
Thu Apr 15 03:20:46 UTC 2004
> Spike: how fast is ELLO? Surely 100KM is long enough to stay below 1G?
Lets estimate it. The diameter of the moon is about 3500 km,
the mass is about one eightieth the earth, so about 7.4e22.
omega^2*R = 7.4E22*6.7E-11/3.5E6^2
so omega = 3.4E-4 and omega*R is the tangential velocity
of about 3.4E-4*3500 is about 1200 meters per second.
One G is about 10 m/s so 1200 = A*t so t = 120 seconds,
length of the track is .5*10*t^2 = 5*120^2 = 70 km of
track needed to accelerate at one G.
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