[extropy-chat] MARS: Because it is hard
Spike
spike66 at comcast.net
Thu Apr 15 04:47:10 UTC 2004
> Alan Eliasen
> Subject: Re: [extropy-chat] MARS: Because it is hard
>
> >
> > Spike: how fast is ELLO? Surely 100KM is long enough to
> stay below 1G?
...
>
> a = v^2 / r
>
...
>
> v = sqrt[g r]
>
...
> g = G m / r^2
...
> v = sqrt[G m / r]
>
> Plugging these numbers into Frink...
>
> v = sqrt[moonmass G / moonradius]
>
> (Frink knows a lot about different planetary bodies. "G",
> "moongravity" and "moonradius" are defined units in its data file.
Alan I agree with your equations to here...
> This gives a velocity of about 1680 m/s.
...but I still get about 1200 m/s here. The 1680 m/s is
square root of 2 times the answer I got. This is
perhaps coincidentally the escape velocity from the
lunar surface.
When in doubt I guess we could just google the answer.
> accelerator will either have to be more than 144 km, or
> you'll need to brake harder.
>
> You can use Frink to plug in your own numbers.
> --
> Alan Eliasen
The factor of square root of 2 explains why your
answer for track length is twice mine. Anyone
want to break the tie?
spike
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