[extropy-chat] glat test

[Adrian Tymes]

--- David <deimtee at optusnet.com.au> wrote:
> Adrian Tymes wrote:
> snip
> > For example, in the infinite grid, connecting two
> > nodes diagonally adjacent: the most direct paths
> (one
> > up then one across, or one across then one up)
> both
> > have a resistance of two.  But the total effective
> > resistance, after calculating in all paths, is
> > (according to another post) the square root of
> two.
> 
> That can't be correct. Ignoring all but the two most
> direct paths you have 2 x 2ohms in parallel, giving
> a resistance of one. The rest of the grid can
> only lower that.
> Perhaps it was half the square root of two - a quick
> calculation including the next two paths indicates
> it would be in that neighbourhood.
> 
> (ie  = 1/(1/2+1/2+1/5+1/5 ....))

Like I said, it was according to another post.  I
didn't check said other post's math.  The point is
that the result is less than two, and both square root
of two and any value less than 1 make that assertion
correct.