[ExI] And now for something completely different

[John Clark]

I'm cooped up at home today like everybody else but I did learn something
new. This formula (1+9^-4^6*7)^3^2^85 is interesting for 2 reasons, the
first is it uses every integer from 1 to 9, the second reason is that it
works out to be
2.718281828459..., if you say that's Euler's constant then you be *almost*
correct but not quite, the formula is not exact, it's only a good
approximation of e. How good an approximation? Pretty good, it only starts
to go bad afer 18 trillion trillion digits!

John K Clark
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