[extropy-chat] glat test

[Spike]

> Simon Dawson

> 
> you know, the thought occurs to me. Often these kinds of 
> tests are the "aha" kind.
> 
> ie, there's a trick.
> 
> in this problem, resistance across a knight's move, perhaps 
> the clue is really "the grid of resistors"
> 
> a grid implies square pattern, right?
> 
> which means you'd have to go UP two resistors, and ACROSS 
> one, to get the knight's move.
> 
> this would mean the sum of 3 resistances.
> 
> Just a thought.
> 
> Si


Well sure.  The way I interpreted the problem is a grid of
squares.  If node A is at (0,0) and node B is at (1,2)
and there is a one-ohm resistor between each node, what
is Req between A and B?  I have solved the case for two
adjacent nodes and two nodes diagonally separated, but
I cannot add the two resistances to get Req A-B.  If I
did, I would be remarkably close to 1 ohm, so I am tempted
to say that is the answer, but I want to prove it.  Its
turned out to be wildly difficult.

HEY OUT THERE have any of you whiz kids gotten a copy
of the GLAT?  Isn't that a cool IQ test?  Im tempted to
apply to work there.

spike